fifteen percent of the pigment in paint color a is black. sixty percent of the pigment in paint color b is…

fifteen percent of the pigment in paint color a is black. sixty percent of the pigment in paint color b is black. an unknown amount of paint color b is mixed with 40 ml of paint color a, resulting in a paint that contains 25% black pigment. which equation can be used to solve for x, the total amount of paint in the mixture of the two colors? 0.15(40)+0.6x = 0.25(40 + x) 0.15(40)+0.6(x - 40)=0.25(x) 0.15(40)+0.6x = 0.25(40 - x) 0.15(40)+0.6(x + 40)=0.25(x)

fifteen percent of the pigment in paint color a is black. sixty percent of the pigment in paint color b is black. an unknown amount of paint color b is mixed with 40 ml of paint color a, resulting in a paint that contains 25% black pigment. which equation can be used to solve for x, the total amount of paint in the mixture of the two colors? 0.15(40)+0.6x = 0.25(40 + x) 0.15(40)+0.6(x - 40)=0.25(x) 0.15(40)+0.6x = 0.25(40 - x) 0.15(40)+0.6(x + 40)=0.25(x)

Answer

Explanation:

Step1: Calculate black pigment in paint A

The amount of paint A is 40 ml and 15% of it is black pigment. So the amount of black pigment in paint A is $0.15\times40$.

Step2: Calculate black pigment in paint B

The total amount of the mixture is $x$ ml and the amount of paint A is 40 ml, so the amount of paint B is $(x - 40)$ ml. Since 60% of paint B is black pigment, the amount of black pigment in paint B is $0.6(x - 40)$.

Step3: Calculate black pigment in the mixture

The total amount of the mixture is $x$ ml and 25% of it is black pigment. So the amount of black pigment in the mixture is $0.25x$.

Step4: Set up the equation

The sum of black - pigment in paint A and paint B equals the black - pigment in the mixture. So the equation is $0.15(40)+0.6(x - 40)=0.25x$.

Answer:

$0.15(40)+0.6(x - 40)=0.25x$