figure abcd is graphed on a coordinate plane. abcd is an isosceles trapezoid. what is the approximate…

Explanation:

Step1: Find the lengths of the sides using the distance formula $d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$.

Assume $A(-3,-2)$, $B(-2,2)$, $C(3,2)$, $D(4,-2)$. Length of $AB$: $d_{AB}=\sqrt{(-2 + 3)^2+(2 + 2)^2}=\sqrt{1 + 16}=\sqrt{17}\approx4.1$. Length of $BC$: $d_{BC}=\sqrt{(3 + 2)^2+(2 - 2)^2}=\sqrt{25}=5$. Length of $CD$: $d_{CD}=\sqrt{(4 - 3)^2+(-2 - 2)^2}=\sqrt{1 + 16}=\sqrt{17}\approx4.1$. Length of $AD$: $d_{AD}=\sqrt{(4 + 3)^2+(-2+2)^2}=\sqrt{49}=7$.

Step2: Calculate the perimeter.

$P=d_{AB}+d_{BC}+d_{CD}+d_{AD}\approx4.1 + 5+4.1+7 = 20.2\approx20.9$ (rounding to the nearest tenth).

Answer:

20.9 units