figure abcd is a kite. the area of abcd is 48 square units. the length of line segment bd is 8 units. what…

Explanation:

Step1: Recall area formula for kite

The area formula for a kite is $A=\frac{1}{2}d_1d_2$, where $d_1$ and $d_2$ are the lengths of the diagonals. Here, let $d_1 = BD$ and $d_2=AC$.

Step2: Substitute known values

We know that $A = 48$ square - units and $d_1=BD = 8$ units. Substituting into the formula $A=\frac{1}{2}d_1d_2$, we get $48=\frac{1}{2}\times8\times d_2$.

Step3: Solve for $d_2$

First, simplify the right - hand side of the equation: $\frac{1}{2}\times8\times d_2 = 4d_2$. So, the equation becomes $48 = 4d_2$. Then, divide both sides by 4: $d_2=\frac{48}{4}=12$ units.

Answer:

D. 12 units