figure abcd is a parallelogram. which sequence could be used to prove that ad = bc? first prove △abc is…

figure abcd is a parallelogram. which sequence could be used to prove that ad = bc? first prove △abc is congruent to △cda, and then state ad and bc are corresponding sides of the triangles. first prove △abc is similar to △cda, and then state ad and bc are opposite sides of the parallelograms. first prove ▱abcd is congruent to ▱cdab, and then state ad and bc are corresponding sides of two parallelograms. first prove ▱abcd is similar to ▱cdab, and then state ad and bc are opposite sides of the parallelograms.
Answer
Answer:
First prove $\triangle ABC$ is congruent to $\triangle CDA$, and then state $\overline{AD}$ and $\overline{BC}$ are corresponding sides of the triangles.
Explanation:
Step1: Recall parallelogram properties
In parallelogram $ABCD$, $AB\parallel CD$, $AD\parallel BC$, $\angle BAC=\angle DCA$, $\angle ACB = \angle CAD$, and $AC = CA$ (common - side).
Step2: Prove triangle congruence
By the Angle - Side - Angle (ASA) congruence criterion, $\triangle ABC\cong\triangle CDA$.
Step3: Identify corresponding sides
Since $\triangle ABC\cong\triangle CDA$, $\overline{AD}$ and $\overline{BC}$ are corresponding sides of the congruent triangles, so $AD = BC$.