find the 59th term of the arithmetic sequence 26, 17, 8, ...

find the 59th term of the arithmetic sequence 26, 17, 8, ...

find the 59th term of the arithmetic sequence 26, 17, 8, ...

Answer

Explanation:

Step1: Find the common difference

The common difference $d$ of an arithmetic sequence is found by subtracting the first - term from the second - term. Here, $a_1 = 26$, $a_2 = 17$, so $d=a_2 - a_1=17 - 26=-9$.

Step2: Use the formula for the $n$th term of an arithmetic sequence

The formula for the $n$th term of an arithmetic sequence is $a_n=a_1+(n - 1)d$. We want to find the 59th term, so $n = 59$, $a_1 = 26$, and $d=-9$. Substitute these values into the formula: $a_{59}=26+(59 - 1)\times(-9)$.

Step3: Simplify the expression

First, calculate the value inside the parentheses: $59 - 1 = 58$. Then, multiply: $58\times(-9)=-522$. Finally, add: $a_{59}=26+( - 522)=26-522=-496$.

Answer:

$-496$