find $m\\angle t$.\n$m\\angle t = \\square^\\circ$\nsubmit

find $m\\angle t$.\n$m\\angle t = \\square^\\circ$\nsubmit

find $m\\angle t$.\n$m\\angle t = \\square^\\circ$\nsubmit

Answer

T$, as we have opposite side $SU$ and hypotenuse $TS$. $\sin(\angle T) = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{3\sqrt{3}}{6\sqrt{3}}$

Step2: Simplify the ratio

Cancel $\sqrt{3}$ and reduce the fraction. $\sin(\angle T) = \frac{3}{6} = \frac{1}{2}$

Step3: Find angle measure

Use inverse sine for the value $\frac{1}{2}$. $\angle T = \sin^{-1}\left(\frac{1}{2}\right) = 30^\circ$

Answer:

$30$