find the difference of these matrices. if its impossible, type impossible. a = \\( \\begin{bmatrix} - 10…

find the difference of these matrices. if its impossible, type impossible. a = \\( \\begin{bmatrix} - 10 \\\\ 7 \\end{bmatrix} \\) b = \\( \\begin{bmatrix} 0 & - 8 \\end{bmatrix} \\) a - b = \\( \\begin{bmatrix} ? \\\\ \\square \\end{bmatrix} \\)

find the difference of these matrices. if its impossible, type impossible. a = \\( \\begin{bmatrix} - 10 \\\\ 7 \\end{bmatrix} \\) b = \\( \\begin{bmatrix} 0 & - 8 \\end{bmatrix} \\) a - b = \\( \\begin{bmatrix} ? \\\\ \\square \\end{bmatrix} \\)

Answer

Explanation:

Step1: Multiply the scalar with each element of the matrix

When multiplying a scalar (k = 8) with a matrix (\begin{bmatrix}-1\12\3\end{bmatrix}), we use the rule (k\begin{bmatrix}a\b\c\end{bmatrix}=\begin{bmatrix}ka\kb\kc\end{bmatrix}). For the first - element: (8\times(-1)) (8\times(-1)=- 8)

Step2: Multiply the scalar with the second element of the matrix

For the second - element: (8\times12) (8\times12 = 96)

Step3: Multiply the scalar with the third element of the matrix

For the third - element: (8\times3) (8\times3=24)

Answer:

(\begin{bmatrix}-8\96\24\end{bmatrix})