find the equation of the axis of symmetry of the following parabola algebraically. y = -x² - 2x + 7
find the equation of the axis of symmetry of the following parabola algebraically. y = -x² - 2x + 7
Answer
Explanation:
Step1: Identify coefficients
For the quadratic function (y = ax^{2}+bx + c), in (y=-x^{2}-2x + 7), (a=-1), (b = - 2), (c = 7).
Step2: Use axis - of - symmetry formula
The formula for the axis of symmetry of a parabola (y = ax^{2}+bx + c) is (x=-\frac{b}{2a}). Substitute (a=-1) and (b=-2) into the formula: (x=-\frac{-2}{2\times(-1)}) First, calculate the denominator (2\times(-1)=-2), and the numerator (-(-2) = 2). Then (x=\frac{2}{-2}=-1)
Answer:
The equation of the axis of symmetry is (x=-1)