find the equation of the axis of symmetry for the parabola y = x^2 - 4x. simplify any numbers and write them…

Explanation:

Step1: Recall the formula for axis of symmetry

For a parabola in the form $y = ax^{2}+bx + c$, the axis - of - symmetry is given by the formula $x=-\frac{b}{2a}$.

Step2: Identify the values of a and b

For the parabola $y=x^{2}-4x$, we have $a = 1$ and $b=-4$.

Step3: Calculate the axis of symmetry

Substitute $a = 1$ and $b=-4$ into the formula $x =-\frac{b}{2a}$. We get $x=-\frac{-4}{2\times1}=\frac{4}{2}=2$.

Answer:

$x = 2$