find the missing factor d that makes the equality true. -15y^4=(d)(3y^2) d =
find the missing factor d that makes the equality true. -15y^4=(d)(3y^2) d =
Answer
Explanation:
Step1: Isolate D.
Divide both sides by $3y^{2}$. So $D=\frac{- 15y^{4}}{3y^{2}}$.
Step2: Simplify the fraction.
Use the quotient - rule of exponents $\frac{a^{m}}{a^{n}}=a^{m - n}$. Here, $\frac{-15}{3}=-5$ and $\frac{y^{4}}{y^{2}}=y^{4 - 2}=y^{2}$. So $D=-5y^{2}$.
Answer:
$-5y^{2}$