find ( f^{-1} ) for the one - to - one function ( f ).\n( f(x)=\frac{1}{x} )\n( f^{-1}(x)= )

find ( f^{-1} ) for the one - to - one function ( f ).\n( f(x)=\frac{1}{x} )\n( f^{-1}(x)= )

find ( f^{-1} ) for the one - to - one function ( f ).\n( f(x)=\frac{1}{x} )\n( f^{-1}(x)= )

Answer

Explanation:

Step1: Set ( y = f(x) )

Given ( f(x)=\frac{1}{x} ), so ( y = \frac{1}{x} ).

Step2: Swap ( x ) and ( y )

After swapping, we get ( x=\frac{1}{y} ).

Step3: Solve for ( y )

Multiply both sides by ( y ): ( xy = 1 ). Then ( y=\frac{1}{x} ).

Answer:

( f^{-1}(x)=\frac{1}{x} )