find the product.\n$\begin{bmatrix}6&0\\4& - 3\\-3&-2end{bmatrix}\begin{bmatrix}3\\-5end{bmatrix}$

Explanation:

Step1: Multiply first - row elements by column elements

Multiply elements of first row of first matrix by corresponding elements of the column matrix and sum them. $6\times3 + 0\times(-5)=18 + 0=18$

Step2: Multiply second - row elements by column elements

Multiply elements of second row of first matrix by corresponding elements of the column matrix and sum them. $4\times3+(-3)\times(-5)=12 + 15=27$

Step3: Multiply third - row elements by column elements

Multiply elements of third row of first matrix by corresponding elements of the column matrix and sum them. $(-3)\times3+(-2)\times(-5)=-9 + 10 = 1$

Answer:

$\begin{bmatrix}18\27\1\end{bmatrix}$