find the slope of the line that passes through the given coordinates\n3. (-1, 6) and (4, 3)\n4. (29, 11) and…

find the slope of the line that passes through the given coordinates\n3. (-1, 6) and (4, 3)\n4. (29, 11) and (-3, -7)\n5. (11, 7) and crosses the y - axis at 17.
Answer
Explanation:
Step1: Recall slope - formula
The slope formula for two points $(x_1,y_1)$ and $(x_2,y_2)$ is $m=\frac{y_2 - y_1}{x_2 - x_1}$.
Step2: Solve for problem 3
Let $(x_1,y_1)=(-1,6)$ and $(x_2,y_2)=(4,3)$. Then $m=\frac{3 - 6}{4-(-1)}=\frac{-3}{5}=-\frac{3}{5}$.
Step3: Solve for problem 4
Let $(x_1,y_1)=(2,9)$ and $(x_2,y_2)=(-3,-7)$. Then $m=\frac{-7 - 9}{-3 - 2}=\frac{-16}{-5}=\frac{16}{5}$.
Step4: Solve for problem 5
The line crosses the $y$-axis at $(0,17)$ and another point is $(11,7)$. Let $(x_1,y_1)=(0,17)$ and $(x_2,y_2)=(11,7)$. Then $m=\frac{7 - 17}{11-0}=\frac{-10}{11}=-\frac{10}{11}$.
Answer:
- $-\frac{3}{5}$
- $\frac{16}{5}$
- $-\frac{10}{11}$