find the sum of (-4 + i) and (10 - 5i).\n-3 + 5i\n-3 - 5i\n6 - 4i\n6 - 6i
find the sum of (-4 + i) and (10 - 5i).\n-3 + 5i\n-3 - 5i\n6 - 4i\n6 - 6i
Answer
Explanation:
Step1: Add real - parts
Add the real parts of the two complex numbers: $-4 + 10=6$.
Step2: Add imaginary - parts
Add the imaginary parts of the two complex numbers: $1i+( - 5i)=(1 - 5)i=-4i$.
Step3: Combine results
Combine the results of the real - part addition and the imaginary - part addition. The sum is $6-4i$.
Answer:
C. $6 - 4i$