find the sum of (-4 + i) and (10 - 5i).\n-3 + 5i\n-3 - 5i\n6 - 4i\n6 - 6i\ndone

find the sum of (-4 + i) and (10 - 5i).\n-3 + 5i\n-3 - 5i\n6 - 4i\n6 - 6i\ndone

find the sum of (-4 + i) and (10 - 5i).\n-3 + 5i\n-3 - 5i\n6 - 4i\n6 - 6i\ndone

Answer

Explanation:

Step1: Add real - parts

Add the real parts of the two complex numbers: $-4 + 10=6$.

Step2: Add imaginary - parts

Add the imaginary parts of the two complex numbers: $1+( - 5)=1 - 5=-4$.

Step3: Combine real and imaginary parts

The sum of the two complex numbers is $6+( - 4)i = 6-4i$.

Answer:

$6 - 4i$