find the sum: $4sqrt{3}+11sqrt{12}$\n$15sqrt{15}$\n$15sqrt{3}$\n$26sqrt{3}$\n$48sqrt{3}$

Answer:

C. $26\sqrt{3}$

Explanation:

Step1: Simplify $\sqrt{12}$

$\sqrt{12}=\sqrt{4\times3}=2\sqrt{3}$

Step2: Substitute into original expression

$4\sqrt{3}+11\sqrt{12}=4\sqrt{3}+11\times2\sqrt{3}$

Step3: Calculate the second - term

$11\times2\sqrt{3} = 22\sqrt{3}$

Step4: Combine like - terms

$4\sqrt{3}+22\sqrt{3}=(4 + 22)\sqrt{3}=26\sqrt{3}$