find the value of x. round to the nearest tenth.

Explanation:

Step1: Apply Pythagorean theorem

In a right - triangle, (a^{2}+b^{2}=c^{2}), where (c) is the hypotenuse. Here (a = 7), (b = 4), and (x) is the hypotenuse. So (x=\sqrt{7^{2}+4^{2}}).

Step2: Calculate the squares

(7^{2}=49) and (4^{2}=16). Then (x=\sqrt{49 + 16}).

Step3: Add the numbers inside the square - root

(49+16 = 65), so (x=\sqrt{65}).

Step4: Round to the nearest tenth

(\sqrt{65}\approx 8.1)

Answer:

8.1