find the value of $x$ in the triangle shown below.\n$x = square^{circ}$
find the value of $x$ in the triangle shown below.\n$x = square^{circ}$
Answer
Explanation:
Step1: Recognize the triangle type
This is an isosceles triangle (two sides are equal, both (3.3)). In an isosceles triangle, the angles opposite the equal sides are equal.
Step2: Use the angle - sum property of a triangle
The sum of angles in a triangle is (180^{\circ}). Let the angle opposite the side of length (5.1) be (y). We know (x + x+39^{\circ}=180^{\circ}) (since the two angles opposite the sides of length (3.3) are equal, both (x)). Simplify the equation: (2x=180^{\circ}- 39^{\circ}) (2x = 141^{\circ}) Then (x=\frac{141^{\circ}}{2})
Answer:
(70.5)