find the vertex of the parabola ( y = -3x^{2} ).\nsimplify both coordinates and write them as proper…

find the vertex of the parabola ( y = -3x^{2} ).\nsimplify both coordinates and write them as proper fractions, improper fractions, or integers.\n( , )

find the vertex of the parabola ( y = -3x^{2} ).\nsimplify both coordinates and write them as proper fractions, improper fractions, or integers.\n( , )

Answer

Explanation:

Step1: Recall the vertex form of a parabola

The general form of a parabola is (y = ax^{2}+bx + c). For the parabola (y=-3x^{2}), we have (a=-3), (b = 0), and (c = 0). The (x) - coordinate of the vertex of a parabola given by (y = ax^{2}+bx + c) is (x=-\frac{b}{2a}). Substituting (b = 0) and (a=-3) into the formula (x =-\frac{b}{2a}), we get (x=-\frac{0}{2\times(-3)}=0).

Step2: Find the (y) - coordinate

Substitute (x = 0) into the equation (y=-3x^{2}). Then (y=-3\times(0)^{2}=0).

Answer:

((0,0))