find the vertex of the parabola y = x^2. simplify both coordinates and write them as proper fractions…

Explanation:

Step1: Recall vertex - form of parabola

The general vertex - form of a parabola is $y=a(x - h)^2+k$, where $(h,k)$ is the vertex of the parabola. For the parabola $y=x^{2}$, we can rewrite it as $y = 1(x - 0)^2+0$.

Step2: Identify vertex coordinates

Comparing $y = 1(x - 0)^2+0$ with $y=a(x - h)^2+k$, we have $h = 0$ and $k = 0$.

Answer:

$0,0$