find the vertical asymptote.\ny = \\frac{3x + 6}{3x - 3}\nx = ?

find the vertical asymptote.\ny = \\frac{3x + 6}{3x - 3}\nx = ?

find the vertical asymptote.\ny = \\frac{3x + 6}{3x - 3}\nx = ?

Answer

Explanation:

Step1: Recall vertical - asymptote rule

Vertical asymptotes occur where the denominator of a rational function is zero. Set the denominator equal to zero: $3x - 3=0$.

Step2: Solve the equation for x

Add 3 to both sides: $3x=3$. Divide both sides by 3: $x = 1$.

Answer:

$x = 1$