find wx.\nwrite your answer as an integer or as a decimal rounded to the nearest tenth.\nwx = \nsubmit

find wx.\nwrite your answer as an integer or as a decimal rounded to the nearest tenth.\nwx = \nsubmit

find wx.\nwrite your answer as an integer or as a decimal rounded to the nearest tenth.\nwx = \nsubmit

Answer

Explanation:

Step1: Recall tangent formula

In right - triangle $VXW$, $\tan\theta=\frac{\text{opposite}}{\text{adjacent}}$. Here, $\theta = 28^{\circ}$, the opposite side to $\angle W$ is $VX=\sqrt{15}$, and the adjacent side is $WX$. So, $\tan(28^{\circ})=\frac{VX}{WX}$.

Step2: Solve for $WX$

We can rewrite the formula as $WX=\frac{VX}{\tan(28^{\circ})}$. Since $VX = \sqrt{15}\approx3.87$, and $\tan(28^{\circ})\approx0.5317$. Then $WX=\frac{3.87}{0.5317}\approx7.3$.

Answer:

$7.3$