the first step in determining the solution to the system of equations, $y = -x^{2}-4x - 3$ and $y = 2x + 5$…

the first step in determining the solution to the system of equations, $y = -x^{2}-4x - 3$ and $y = 2x + 5$, algebraically is to set the two equations equal as $-x^{2}-4x - 3=2x + 5$. what is the next step?\nset $y = 0$ in $y=-x^{2}-4x - 3$.\nfactor each side of the equation.\nuse substitution to create a one - variable equation.\ncombine like terms onto one side of the equation.

the first step in determining the solution to the system of equations, $y = -x^{2}-4x - 3$ and $y = 2x + 5$, algebraically is to set the two equations equal as $-x^{2}-4x - 3=2x + 5$. what is the next step?\nset $y = 0$ in $y=-x^{2}-4x - 3$.\nfactor each side of the equation.\nuse substitution to create a one - variable equation.\ncombine like terms onto one side of the equation.

Answer

Explanation:

Step1: Analyze the given equation

We have (-x^{2}-4x - 3=2x + 5). To solve a quadratic - type equation, we need to get it in standard form (ax^{2}+bx + c = 0).

Step2: Combine like - terms

We move all terms to one side of the equation. Add (x^{2}) to both sides, add (4x) to both sides, and subtract 5 from both sides. So, (-x^{2}-4x - 3-(2x + 5)=0), which simplifies to (-x^{2}-4x - 3-2x - 5 = 0), and further to (-x^{2}-6x - 8 = 0) (or (x^{2}+6x + 8 = 0) after multiplying through by - 1).

Answer:

Combine like terms onto one side of the equation.