what is the first step in writing f(x) = 6x² + 5 - 42x in vertex form?\nfactor 6 out of each term.\nfactor 6…
what is the first step in writing f(x) = 6x² + 5 - 42x in vertex form?\nfactor 6 out of each term.\nfactor 6 out of the first two terms.\nwrite the function in standard form.\nwrite the trinomial as a binomial squared.
Answer
Brief Explanations:
To convert a quadratic function $f(x)=ax^{2}+bx + c$ to vertex - form $f(x)=a(x - h)^{2}+k$, when $a\neq1$, the first step is to factor out the coefficient of $x^{2}$ from the first two terms. For $f(x)=6x^{2}+5 - 42x$, the coefficient of $x^{2}$ is 6. So we factor 6 out of the first two terms $6x^{2}-42x$.
Answer:
Factor 6 out of the first two terms.