which of the following equations is \\(\\log_{9}(-x - 9) = -2\\) rewritten in exponential form? (1 point)…

which of the following equations is \\(\\log_{9}(-x - 9) = -2\\) rewritten in exponential form? (1 point) \\(9^{-2} = -x - 9\\) \\(-9^{2} = -x - 9\\) \\(9^{-x - 9} = -2\\) \\(9 \\cdot -2 = -x - 9\\)

which of the following equations is \\(\\log_{9}(-x - 9) = -2\\) rewritten in exponential form? (1 point) \\(9^{-2} = -x - 9\\) \\(-9^{2} = -x - 9\\) \\(9^{-x - 9} = -2\\) \\(9 \\cdot -2 = -x - 9\\)

Answer

Explanation:

Step1: Recall the logarithm definition

The logarithmic equation (\log_b(a) = c) can be rewritten in exponential form as (b^c = a). Here, (b = 9), (a=-x - 9), and (c=-2).

Step2: Apply the definition

Substitute the values of (b), (a), and (c) into the exponential form formula. So we get (9^{-2}=-x - 9).

Answer:

A. (9^{-2}=-x - 9)