which of the following is equivalent to \\(\\log \\frac{1}{k}\\)? \\(\\log \\frac{1}{9} + \\log k\\)…

which of the following is equivalent to \\(\\log \\frac{1}{k}\\)? \\(\\log \\frac{1}{9} + \\log k\\) \\(\\log \\frac{1}{9} \\cdot \\log k\\) \\(\\log \\frac{1}{9} - \\log k\\) \\(\\log \\frac{1}{9} \\div \\log k\\)

which of the following is equivalent to \\(\\log \\frac{1}{k}\\)? \\(\\log \\frac{1}{9} + \\log k\\) \\(\\log \\frac{1}{9} \\cdot \\log k\\) \\(\\log \\frac{1}{9} - \\log k\\) \\(\\log \\frac{1}{9} \\div \\log k\\)

Answer

Answer:

$\log \frac{1}{9} - \log k$