which of the following is equivalent to $sqrt{8}$?\n2\n$sqrt{2}$\n$2sqrt{2}$\n$2 + sqrt{2}$

Explanation:

Step1: Factorize the number inside square - root

We know that $8 = 4\times2$. So, $\sqrt{8}=\sqrt{4\times2}$.

Step2: Use the square - root property $\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}$ ($a = 4$, $b = 2$)

$\sqrt{4\times2}=\sqrt{4}\cdot\sqrt{2}$.

Step3: Calculate $\sqrt{4}$

Since $\sqrt{4}=2$, then $\sqrt{4}\cdot\sqrt{2}=2\sqrt{2}$.

Answer:

C. $2\sqrt{2}$