the following figure is a rectangle made up of two smaller rectangles.\n(a) find the area of the following…

the following figure is a rectangle made up of two smaller rectangles.\n(a) find the area of the following (in square units).\nthe dark rectangle (on the top): \nthe light rectangle (on the bottom): \n(b) give the area of the entire figure (in square units) in two different ways.\nas a sum of two areas: \nas a product of the length and width:
Answer
Explanation:
Step1: Calculate area of dark - rectangle
The area formula for a rectangle is $A = l\times w$. For the dark rectangle, length $l = 7$ and width $w = 3$. So, $A_1=7\times3 = 21$.
Step2: Calculate area of light - rectangle
For the light rectangle, length $l = 7$ and width $w = x$. So, $A_2=7\times x=7x$.
Step3: Find area as sum of two areas
The area of the entire figure as a sum of the two smaller rectangles' areas is $A = A_1+A_2=21 + 7x$.
Step4: Find area as product of length and width
The length of the entire rectangle is $3 + x$ and the width is 7. So, $A=7\times(3 + x)=21+7x$.
Answer:
(a) The dark rectangle: 21 The light rectangle: $7x$ (b) As a sum of two areas: $21 + 7x$ As a product of the length and width: $7(3 + x)$