the following figure is a rectangle made up of two smaller rectangles.\n(a) find the area of the following…

the following figure is a rectangle made up of two smaller rectangles.\n(a) find the area of the following (in square units).\nthe light rectangle (on the left): \nthe dark rectangle (on the right): \n(b) give the area of the entire figure (in square units) in two different ways.\nas a sum of two areas: \nas a product of the length and width:

the following figure is a rectangle made up of two smaller rectangles.\n(a) find the area of the following (in square units).\nthe light rectangle (on the left): \nthe dark rectangle (on the right): \n(b) give the area of the entire figure (in square units) in two different ways.\nas a sum of two areas: \nas a product of the length and width:

Answer

Explanation:

Step1: Find area of left - hand rectangle

The area formula for a rectangle is $A = lw$. For the light rectangle on the left with length $l = 9$ and width $w=x$, the area $A_1=9x$.

Step2: Find area of right - hand rectangle

For the dark rectangle on the right with length $l = 9$ and width $w = 4$, the area $A_2=9\times4=36$.

Step3: Find area as sum of two areas

The area of the entire figure as a sum of two areas is $A=A_1 + A_2=9x+36$.

Step4: Find area as product of length and width

The length of the entire rectangle is $9$ and the width is $x + 4$. Using the area formula $A=lw$, we get $A=9(x + 4)$.

Answer:

(a) The light rectangle (on the left): $9x$ The dark rectangle (on the right): $36$ (b) As a sum of two areas: $9x + 36$ As a product of the length and width: $9(x + 4)$