which of the following statements shows how to calculate the reference angle for $\theta =…

which of the following statements shows how to calculate the reference angle for $\theta = \frac{11pi}{6}$?\n$pi - \theta$\n$\theta - pi$\n$2pi - \theta$\ndone

which of the following statements shows how to calculate the reference angle for $\theta = \frac{11pi}{6}$?\n$pi - \theta$\n$\theta - pi$\n$2pi - \theta$\ndone

Answer

Explanation:

Step1: Determine the quadrant of the angle

The angle $\theta=\frac{11\pi}{6}$ is in the fourth - quadrant since $2\pi-\frac{\pi}{6}=\frac{11\pi}{6}$ and angles in the fourth - quadrant satisfy $\frac{3\pi}{2}<\theta < 2\pi$.

Step2: Recall the formula for reference angle in the fourth - quadrant

For an angle $\theta$ in the fourth - quadrant, the reference angle $\alpha$ is given by $\alpha = 2\pi-\theta$.

Answer:

C. $2\pi - \theta$