when the formula ( p = 2l + 2w ) is solved for ( w ), the result is\n(1) ( w=\frac{2l + p}{2} )\n(2) (…

when the formula ( p = 2l + 2w ) is solved for ( w ), the result is\n(1) ( w=\frac{2l + p}{2} )\n(2) ( w=\frac{p - 2l}{2} )\n(3) ( w=\frac{p}{2}+l )\n(4) ( w = l-\frac{p}{2} )

when the formula ( p = 2l + 2w ) is solved for ( w ), the result is\n(1) ( w=\frac{2l + p}{2} )\n(2) ( w=\frac{p - 2l}{2} )\n(3) ( w=\frac{p}{2}+l )\n(4) ( w = l-\frac{p}{2} )

Answer

Explanation:

Step1: Subtract (2l) from both sides

$$p - 2l=2l + 2w-2l[LLM SSE On Failure]