the formula for the area of a trapezoid is $a = \\frac{1}{2}(b_1 + b_2)h$. when this equation is solved for…

the formula for the area of a trapezoid is $a = \\frac{1}{2}(b_1 + b_2)h$. when this equation is solved for $b_1$, one equation is $b_1=\frac{2a}{h}-b_2$. which of the following is an equivalent equation to find $b_1$?\n$b_1=\frac{2a - b_2h}{h}$\n$b_1 = 2a - b_2h$\n$b_1=\frac{h}{2a - b_2h}$\n$b_1=h(2a - b_2h)$

the formula for the area of a trapezoid is $a = \\frac{1}{2}(b_1 + b_2)h$. when this equation is solved for $b_1$, one equation is $b_1=\frac{2a}{h}-b_2$. which of the following is an equivalent equation to find $b_1$?\n$b_1=\frac{2a - b_2h}{h}$\n$b_1 = 2a - b_2h$\n$b_1=\frac{h}{2a - b_2h}$\n$b_1=h(2a - b_2h)$

Answer

Explanation:

Step1: Start with given formula

$b_1=\frac{2A}{h}-b_2$

Step2: Get a common - denominator

$b_1=\frac{2A}{h}-\frac{b_2h}{h}$

Step3: Combine the fractions

$b_1=\frac{2A - b_2h}{h}$

Answer:

$b_1=\frac{2A - b_2h}{h}$ (First option)