when $\frac{2x^{2}}{y}=\frac{w + 2}{4}$ is solved for $w$, one equation is $w=\frac{8x^{2}}{y}-2$. which of…

when $\frac{2x^{2}}{y}=\frac{w + 2}{4}$ is solved for $w$, one equation is $w=\frac{8x^{2}}{y}-2$. which of the following is an equivalent equation to find $w$?\n$w=\frac{8x^{2}+2y}{y}$\n$w=\frac{8x^{2}-2y}{y}$\n$w = 8x^{2}-3y$\n$w = 8x^{2}-y$

when $\frac{2x^{2}}{y}=\frac{w + 2}{4}$ is solved for $w$, one equation is $w=\frac{8x^{2}}{y}-2$. which of the following is an equivalent equation to find $w$?\n$w=\frac{8x^{2}+2y}{y}$\n$w=\frac{8x^{2}-2y}{y}$\n$w = 8x^{2}-3y$\n$w = 8x^{2}-y$

Answer

Explanation:

Step1: Combine fractions

We have $w = \frac{8x^{2}}{y}-2$. Rewrite $2$ as $\frac{2y}{y}$ so we can combine the fractions. Then $w=\frac{8x^{2}}{y}-\frac{2y}{y}$.

Step2: Subtract fractions

Using the rule $\frac{a}{c}-\frac{b}{c}=\frac{a - b}{c}$, we get $w=\frac{8x^{2}-2y}{y}$.

Answer:

$w=\frac{8x^{2}-2y}{y}$ (Second option)