c. $\frac{1}{2}+p = - 3$

c. $\frac{1}{2}+p = - 3$

c. $\frac{1}{2}+p = - 3$

Answer

Explanation:

Step1: Isolate the variable p.

Subtract $\frac{1}{2}$ from both sides of the equation $\frac{1}{2}+p = - 3$. So $p=-3-\frac{1}{2}$.

Step2: Calculate the right - hand side value.

Rewrite $-3$ as $-\frac{6}{2}$. Then $p = -\frac{6}{2}-\frac{1}{2}=-\frac{6 + 1}{2}=-\frac{7}{2}$.

Answer:

$p = -\frac{7}{2}$