3. $\frac{3}{4}-\frac{1}{2}n=\frac{5}{8}$

3. $\frac{3}{4}-\frac{1}{2}n=\frac{5}{8}$

3. $\frac{3}{4}-\frac{1}{2}n=\frac{5}{8}$

Answer

Explanation:

Step1: Isolate the term with n

Subtract $\frac{3}{4}$ from both sides. $\frac{3}{4}-\frac{1}{2}n-\frac{3}{4}=\frac{5}{8}-\frac{3}{4}$ $-\frac{1}{2}n=\frac{5}{8}-\frac{6}{8}$ $-\frac{1}{2}n=-\frac{1}{8}$

Step2: Solve for n

Multiply both sides by - 2. $n = (-\frac{1}{8})\times(-2)$ $n=\frac{1}{4}$

Answer:

$n=\frac{1}{4}$