2. $\frac{m^{9}n^{-5}}{m^{4}}=\frac{m^{square}}{n^{square}}$
2. $\frac{m^{9}n^{-5}}{m^{4}}=\frac{m^{square}}{n^{square}}$
Answer
Explanation:
Step1: Use exponent - division rule
When dividing like - bases $a^m\div a^n=a^{m - n}$, for the $m$ terms, we have $\frac{m^9}{m^4}=m^{9 - 4}$. And for the $n$ term, $n^{-5}$ remains in the numerator. $\frac{m^9n^{-5}}{m^4}=m^{9 - 4}n^{-5}$
Step2: Simplify the exponent of $m$
$9−4 = 5$, so $m^{9 - 4}=m^5$. Also, using the rule $a^{-n}=\frac{1}{a^n}$, $n^{-5}=\frac{1}{n^5}$. $m^{9 - 4}n^{-5}=\frac{m^5}{n^5}$
Answer:
$\frac{m^5}{n^5}$