y≤\\frac{1}{3}x - 1\ny≤\\frac{1}{3}x - 3\nall values that satisfy y≤\\frac{1}{3}x - 1 are solutions.\nall…

Explanation:

Step1: Analyze the inequalities

The two inequalities are $y\leq\frac{1}{3}x - 1$ and $y\leq\frac{1}{3}x - 3$. The line $y = \frac{1}{3}x-3$ is below the line $y=\frac{1}{3}x - 1$ since the $y$-intercept of $y=\frac{1}{3}x - 3$ is - 3 and the $y$-intercept of $y=\frac{1}{3}x - 1$ is - 1.

Step2: Determine the solution set

The solution set of a system of inequalities is the set of all points that satisfy all the inequalities in the system. For $y\leq\frac{1}{3}x - 1$ and $y\leq\frac{1}{3}x - 3$, the region that satisfies both is the region below $y=\frac{1}{3}x - 3$ because if a point $(x,y)$ satisfies $y\leq\frac{1}{3}x - 3$, it automatically satisfies $y\leq\frac{1}{3}x - 1$.

Answer:

All values that satisfy $y\leq\frac{1}{3}x - 3$ are solutions.