what is $\frac{sqrt{12x^{8}}}{sqrt{3x^{2}}}$ in simplest form, where $xgeq0$?\n$2sqrt{3}x^{4}$\n$sqrt{15}x^{5…
what is $\frac{sqrt{12x^{8}}}{sqrt{3x^{2}}}$ in simplest form, where $xgeq0$?\n$2sqrt{3}x^{4}$\n$sqrt{15}x^{5}$\n$2x^{3}$\n$2x^{2}$\ndone
Answer
Explanation:
Step1: Use quotient - rule of square roots
$\frac{\sqrt{12x^{8}}}{\sqrt{3x^{2}}}=\sqrt{\frac{12x^{8}}{3x^{2}}}$
Step2: Simplify the fraction inside the square root
$\sqrt{\frac{12x^{8}}{3x^{2}}}=\sqrt{4x^{6}}$
Step3: Simplify the square - root
$\sqrt{4x^{6}} = 2x^{3}$
Answer:
$2x^{3}$