what is $\frac{sqrt{25x^{2}y^{2}}}{sqrt{xy}}$ in simplest form? assume $xgeq0$ and $ygeq0$.\n$5sqrt{xy}$\n$25…
what is $\frac{sqrt{25x^{2}y^{2}}}{sqrt{xy}}$ in simplest form? assume $xgeq0$ and $ygeq0$.\n$5sqrt{xy}$\n$25sqrt{xy}$\n$sqrt{5xy}$\n$5xysqrt{xy}$
Answer
Explanation:
Step1: Use quotient - rule of square roots
$\frac{\sqrt{25x^{2}y^{2}}}{\sqrt{xy}}=\sqrt{\frac{25x^{2}y^{2}}{xy}}$
Step2: Simplify the fraction inside the square root
$\sqrt{\frac{25x^{2}y^{2}}{xy}}=\sqrt{25xy}$
Step3: Simplify the square - root
$\sqrt{25xy} = 5\sqrt{xy}$
Answer:
A. $5\sqrt{xy}$