8. $1\\frac{2}{7}\\square1\\frac{2}{7}\\times\\frac{5}{5}$\n11. $4\\frac{1}{3}\\times2\\frac{2}{7}\\square2\\…

8. $1\\frac{2}{7}\\square1\\frac{2}{7}\\times\\frac{5}{5}$\n11. $4\\frac{1}{3}\\times2\\frac{2}{7}\\square2\\frac{2}{7}$\n14. $4\\frac{3}{4}\\times3\\frac{1}{4}\\square4\\frac{3}{4}$\n17. $\\frac{5}{5}\\times4\\frac{2}{3}\\square4\\frac{2}{3}$
Answer
Explanation:
Step1: Convert mixed - numbers to improper fractions
For (1\frac{2}{7}=\frac{1\times7 + 2}{7}=\frac{9}{7}), (4\frac{1}{3}=\frac{4\times3+1}{3}=\frac{13}{3}), (2\frac{2}{7}=\frac{2\times7 + 2}{7}=\frac{16}{7}), (4\frac{3}{4}=\frac{4\times4+3}{4}=\frac{19}{4}), (3\frac{1}{4}=\frac{3\times4 + 1}{4}=\frac{13}{4}), (4\frac{2}{3}=\frac{4\times3+2}{3}=\frac{14}{3}).
Step2: Calculate the products
For (1\frac{2}{7}) and (1\frac{2}{7}\times\frac{5}{5}):
Since (\frac{5}{5}=1), then (1\frac{2}{7}\times\frac{5}{5}=1\frac{2}{7}), so (1\frac{2}{7}=1\frac{2}{7}\times\frac{5}{5}), the symbol is (=).
For (4\frac{1}{3}\times2\frac{2}{7}) and (2\frac{2}{7}):
(4\frac{1}{3}\times2\frac{2}{7}=\frac{13}{3}\times\frac{16}{7}=\frac{208}{21}\approx9.9), and (2\frac{2}{7}=\frac{16}{7}\approx2.3). So (4\frac{1}{3}\times2\frac{2}{7}>2\frac{2}{7}), the symbol is (>).
For (4\frac{3}{4}\times3\frac{1}{4}) and (4\frac{3}{4}):
(4\frac{3}{4}\times3\frac{1}{4}=\frac{19}{4}\times\frac{13}{4}=\frac{247}{16}\approx15.4), and (4\frac{3}{4}=\frac{19}{4} = 4.75). So (4\frac{3}{4}\times3\frac{1}{4}>4\frac{3}{4}), the symbol is (>).
For (\frac{5}{5}\times4\frac{2}{3}) and (4\frac{2}{3}):
Since (\frac{5}{5}=1), then (\frac{5}{5}\times4\frac{2}{3}=4\frac{2}{3}), so the symbol is (=).
Answer:
- (=)
- (>)
- (>)
- (=)