b) $\frac{1}{2^{3}} \times \frac{1}{3^{2}}$

b) $\frac{1}{2^{3}} \times \frac{1}{3^{2}}$

b) $\frac{1}{2^{3}} \times \frac{1}{3^{2}}$

Answer

Explanation:

Step1: Calculate exponents first

$2^3=8$, $3^2=9$

Step2: Multiply the fractions

$\frac{1}{8} \times \frac{1}{9} = \frac{1 \times 1}{8 \times 9}$

Step3: Simplify the product

$\frac{1}{72}$

Answer:

$\frac{1}{72}$