if $g(x)=\\frac{x+1}{x-2}$ and $h(x)=4-x$, what is the value of $(g\\circ h)(-3)$?\n$\\frac{8}{5}$\n$\\frac{5…

if $g(x)=\\frac{x+1}{x-2}$ and $h(x)=4-x$, what is the value of $(g\\circ h)(-3)$?\n$\\frac{8}{5}$\n$\\frac{5}{2}$\n$\\frac{15}{2}$\n$\\frac{18}{5}$

if $g(x)=\\frac{x+1}{x-2}$ and $h(x)=4-x$, what is the value of $(g\\circ h)(-3)$?\n$\\frac{8}{5}$\n$\\frac{5}{2}$\n$\\frac{15}{2}$\n$\\frac{18}{5}$

Answer

Explanation:

Step1: Calculate $h(-3)$

$h(-3)=4-(-3)=4+3=7$

Step2: Substitute into $g(x)$

$g(h(-3))=g(7)=\frac{7+1}{7-2}$

Step3: Simplify the fraction

$\frac{7+1}{7-2}=\frac{8}{5}$

Answer:

$\frac{8}{5}$ (Option A)