which function is the inverse of $f(x)=2x + 3$?\n$\\circ f^{-1}(x)=-\\frac{1}{2}x-\\frac{3}{2}$\n$\\circ…

which function is the inverse of $f(x)=2x + 3$?\n$\\circ f^{-1}(x)=-\\frac{1}{2}x-\\frac{3}{2}$\n$\\circ f^{-1}(x)=\\frac{1}{2}x-\\frac{3}{2}$\n$\\circ f^{-1}(x)=-2x + 3$\n$\\circ f^{-1}(x)=2x + 3$

which function is the inverse of $f(x)=2x + 3$?\n$\\circ f^{-1}(x)=-\\frac{1}{2}x-\\frac{3}{2}$\n$\\circ f^{-1}(x)=\\frac{1}{2}x-\\frac{3}{2}$\n$\\circ f^{-1}(x)=-2x + 3$\n$\\circ f^{-1}(x)=2x + 3$

Answer

Explanation:

Step1: Let $y = f(x)$

$y = 2x+3$

Step2: Solve for $x$ in terms of $y$

$y-3 = 2x$, then $x=\frac{y - 3}{2}=\frac{1}{2}y-\frac{3}{2}$

Step3: Replace $x$ with $f^{-1}(x)$ and $y$ with $x$

$f^{-1}(x)=\frac{1}{2}x-\frac{3}{2}$

Answer:

B. $f^{-1}(x)=\frac{1}{2}x-\frac{3}{2}$