which function has an inverse that is also a function?\n{(-4, 3), (-2, 7), (-1, 0), (4, -3), (11…

Explanation:

Step1: Recall the condition for inverse to be a function

A function has an inverse that is also a function if and only if the original function is one - to - one. A one - to - one function has no two different input values that produce the same output value.

Step2: Check each set of ordered pairs

For the set ${(-4,3),(-2,7),(-1,0),(4, - 3),(11,-7)}$, each $x$ - value has a unique $y$ - value. For the set ${(-4,6),(-2,2),(-1,6),(4,2),(11,2)}$, the $y$ - value $2$ is repeated for $x=-2,4,11$ and $y = 6$ is repeated for $x=-4,-1$, so it is not one - to - one. For the set ${(-4,5),(-2,9),(-1,8),(4,8),(11,4)}$, the $y$ - value $8$ is repeated for $x=-1$ and $x = 4$, so it is not one - to - one. For the set ${(-4,4),(-2,-1),(-1,0),(4,1),(11,1)}$, the $y$ - value $1$ is repeated for $x = 4$ and $x=11$, so it is not one - to - one.

Answer:

${(-4,3),(-2,7),(-1,0),(4, - 3),(11,-7)}$