which function has real zeros at x = -10 and x = -6?\no f(x)=x² + 16x + 60\no f(x)=x² - 16x + 60\no f(x)=x²…
which function has real zeros at x = -10 and x = -6?\no f(x)=x² + 16x + 60\no f(x)=x² - 16x + 60\no f(x)=x² + 4x + 60\no f(x)=x² - 4x + 60
Answer
Explanation:
Step1: Recall zero - product property
If (x = a) and (x = b) are zeros of a quadratic function, then the function can be written as (f(x)=(x - a)(x - b)). Here (a=-10) and (b = - 6).
Step2: Expand the factored form
[ \begin{align*} f(x)&=(x-(-10))(x - (-6))\ &=(x + 10)(x+6)\ &=x^{2}+6x+10x + 60\ &=x^{2}+16x + 60 \end{align*} ]
Answer:
(f(x)=x^{2}+16x + 60)