b) $3 - 2(x - 4) geq -1$

b) $3 - 2(x - 4) geq -1$

b) $3 - 2(x - 4) geq -1$

Answer

Explanation:

Step1: Expand the expression

$3-2(x - 4)=3-2x + 8$

Step2: Simplify the left - hand side

$3-2x + 8=11-2x$ So the inequality becomes $11-2x\geq - 1$

Step3: Isolate the variable term

Subtract 11 from both sides: $11-2x-11\geq - 1-11$, which simplifies to $-2x\geq - 12$

Step4: Solve for x

Divide both sides by - 2. When dividing an inequality by a negative number, the direction of the inequality sign changes. So $\frac{-2x}{-2}\leq\frac{-12}{-2}$, which gives $x\leq6$

Answer:

$x\leq6$