given $log_{4}3 \\approx 0.792$ and $log_{4}21 \\approx 2.196$, what is $log_{4}7$?\n1.404\n1.739\n2.773\n2.9…

given $log_{4}3 \\approx 0.792$ and $log_{4}21 \\approx 2.196$, what is $log_{4}7$?\n1.404\n1.739\n2.773\n2.988

given $log_{4}3 \\approx 0.792$ and $log_{4}21 \\approx 2.196$, what is $log_{4}7$?\n1.404\n1.739\n2.773\n2.988

Answer

Explanation:

Step1: Split log using quotient rule

$\log_4 7 = \log_4\left(\frac{21}{3}\right) = \log_4 21 - \log_4 3$

Step2: Substitute given values

$\log_4 7 \approx 2.196 - 0.792$

Step3: Calculate the difference

$2.196 - 0.792 = 1.404$

Answer:

1.404