go step by step to reduce the radical. $sqrt{243}$ $sqrt{square}sqrt{square}$

Explanation:

Step1: Factorize 243

Find the prime - factorization of 243. We know that (243 = 81\times3), and (81 = 9\times9=3^4). So (243 = 3^5). Then (\sqrt{243}=\sqrt{81\times3}).

Step2: Use the square - root property (\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}) ((a = 81), (b = 3))

(\sqrt{81\times3}=\sqrt{81}\cdot\sqrt{3}) Since (\sqrt{81}=9), we have (\sqrt{243}=9\sqrt{3})

Answer:

(9\sqrt{3})