graph the circle x² + y² = 81. plot the center. then plot a point on the circle. if you make a mistake, you…

graph the circle x² + y² = 81. plot the center. then plot a point on the circle. if you make a mistake, you can erase your circle by moving the second point onto the first.
Answer
Explanation:
Step1: Recall circle - equation form
The standard form of a circle equation is $(x - a)^2+(y - b)^2=r^2$, where $(a,b)$ is the center and $r$ is the radius. For the equation $x^{2}+y^{2}=81$, we can rewrite it as $(x - 0)^2+(y - 0)^2 = 9^2$. So the center is $(0,0)$ and the radius $r = 9$.
Step2: Plot the center
Plot the point $(0,0)$ on the coordinate - plane.
Step3: Plot a point on the circle
We can find a point on the circle by using the radius. For example, when $x = 9$ and $y = 0$ (since $x^{2}+y^{2}=81$, substituting $x = 9$ gives $9^{2}+0^{2}=81$). Plot the point $(9,0)$ on the circle.
To graph the full circle, we can find other points by symmetry. The circle is symmetric about the $x$ - axis, $y$ - axis, and the origin.
Answer:
Center: $(0,0)$; A point on the circle: $(9,0)$ (There are many other possible points on the circle such as $(0,9),(- 9,0),(0, - 9)$ etc.)