graph the exponential function.\n\n$f(x)=3^{x}$\n\nplot five points on the graph of the function, and also…

Explanation:

Step1: Find points for (x = - 2)

Substitute (x=-2) into (f(x)=3^{x}), we get (f(-2)=3^{-2}=\frac{1}{9}\approx0.11). So the point is ((-2,\frac{1}{9})).

Step2: Find points for (x=-1)

Substitute (x = - 1) into (f(x)=3^{x}), we get (f(-1)=3^{-1}=\frac{1}{3}\approx0.33). So the point is ((-1,\frac{1}{3})).

Step3: Find points for (x = 0)

Substitute (x = 0) into (f(x)=3^{x}), we get (f(0)=3^{0}=1). So the point is ((0,1)).

Step4: Find points for (x = 1)

Substitute (x = 1) into (f(x)=3^{x}), we get (f(1)=3^{1}=3). So the point is ((1,3)).

Step5: Find points for (x = 2)

Substitute (x = 2) into (f(x)=3^{x}), we get (f(2)=3^{2}=9). So the point is ((2,9)). The horizontal - asymptote of the exponential function (y = a^{x}) ((a>0,a\neq1)) is (y = 0).

Answer:

The five points are ((-2,\frac{1}{9}),(-1,\frac{1}{3}),(0,1),(1,3),(2,9)) and the horizontal asymptote is (y = 0).